![SOLVED: The Relation Between Ka and Kb of a Conjugate Acid-Base Pair A key relationship exists between the Ka of HA and the Kb of its conjugate base, A-, which we can SOLVED: The Relation Between Ka and Kb of a Conjugate Acid-Base Pair A key relationship exists between the Ka of HA and the Kb of its conjugate base, A-, which we can](https://cdn.numerade.com/ask_previews/895fc8aa-e558-4ce3-baea-4f4b420d918c_large.jpg)
SOLVED: The Relation Between Ka and Kb of a Conjugate Acid-Base Pair A key relationship exists between the Ka of HA and the Kb of its conjugate base, A-, which we can
![From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw . From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw .](https://haygot.s3.amazonaws.com/questions/1612500_1740151_ans_bdfb34fc466e41398c65a3412f1b4f83.jpg)
From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw .
What is value of Ka and kb for water (H20) and how numerically prove that ka ×kb=kw in case of water? - Quora
![From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw . From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw .](https://haygot.s3.amazonaws.com/questions/1608485_1740056_ans_85323eb8ce264097bbbec05b4cddfb7e.jpg)
From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw .
![SOLVED: Helpful Equations pH = -log [H2O+] Kw = Ka × Kb [ATJ[H2O+1 [HA]] = pOH -log [OH-] 14 = pH + pOH [HA][OH-] [A-] Kb Henderson-Hasselbalch Equation [A-] pH = pKa log - [HA] SOLVED: Helpful Equations pH = -log [H2O+] Kw = Ka × Kb [ATJ[H2O+1 [HA]] = pOH -log [OH-] 14 = pH + pOH [HA][OH-] [A-] Kb Henderson-Hasselbalch Equation [A-] pH = pKa log - [HA]](https://cdn.numerade.com/ask_images/9f4de4f19628424f8aea53cff3ecadcb.jpg)